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12025216503103 = 109873109446511
BaseRepresentation
bin1010111011111101011011…
…0000100000110100111111
31120120121012000101012000211
42232333112300200310333
53034010120411044403
641324150323133251
72350536034524166
oct256772660406477
946517160335024
1012025216503103
113916958245911
121422698814227
13692c85a3ac3b
142d8048a023dd
1515cc0bb0c06d
hexaefd6c20d3f

12025216503103 has 4 divisors (see below), whose sum is σ = 12025326059488. Its totient is φ = 12025106946720.

The previous prime is 12025216503029. The next prime is 12025216503107. The reversal of 12025216503103 is 30130561252021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12025216503103 - 213 = 12025216494911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12025216503107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54613383 + ... + 54833128.

It is an arithmetic number, because the mean of its divisors is an integer number (3006331514872).

Almost surely, 212025216503103 is an apocalyptic number.

12025216503103 is a deficient number, since it is larger than the sum of its proper divisors (109556385).

12025216503103 is a wasteful number, since it uses less digits than its factorization.

12025216503103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109556384.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 12025216503103 its reverse (30130561252021), we get a palindrome (42155777755124).

The spelling of 12025216503103 in words is "twelve trillion, twenty-five billion, two hundred sixteen million, five hundred three thousand, one hundred three".

Divisors: 1 109873 109446511 12025216503103