Base | Representation |
---|---|
bin | 111000000000001110… |
… | …0101010011011001101 |
3 | 102111102120211012022220 |
4 | 1300000130222123031 |
5 | 3432301222114333 |
6 | 131125534325553 |
7 | 11455214134215 |
oct | 1600034523315 |
9 | 374376735286 |
10 | 120266598093 |
11 | 470063a5224 |
12 | 1b3850598b9 |
13 | b4584bb915 |
14 | 5b6c903245 |
15 | 31dd5b78b3 |
hex | 1c0072a6cd |
120266598093 has 4 divisors (see below), whose sum is σ = 160355464128. Its totient is φ = 80177732060.
The previous prime is 120266598071. The next prime is 120266598119. The reversal of 120266598093 is 390895662021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 390895662021 = 3 ⋅130298554007.
It is a cyclic number.
It is not a de Polignac number, because 120266598093 - 25 = 120266598061 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120266598493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20044433013 + ... + 20044433018.
It is an arithmetic number, because the mean of its divisors is an integer number (40088866032).
Almost surely, 2120266598093 is an apocalyptic number.
It is an amenable number.
120266598093 is a deficient number, since it is larger than the sum of its proper divisors (40088866035).
120266598093 is an equidigital number, since it uses as much as digits as its factorization.
120266598093 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40088866034.
The product of its (nonzero) digits is 1399680, while the sum is 51.
The spelling of 120266598093 in words is "one hundred twenty billion, two hundred sixty-six million, five hundred ninety-eight thousand, ninety-three".
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