Base | Representation |
---|---|
bin | 10001100000011010110… |
… | …001011100100010010001 |
3 | 11021000020221000202001112 |
4 | 101200122301130202101 |
5 | 124202311220344213 |
6 | 2320400254343105 |
7 | 152626311245030 |
oct | 21403261344221 |
9 | 4230227022045 |
10 | 1203040012433 |
11 | 42422a7a6466 |
12 | 1751a77baa95 |
13 | 895a536b62c |
14 | 42328188717 |
15 | 21461a34ea8 |
hex | 1181ac5c891 |
1203040012433 has 8 divisors (see below), whose sum is σ = 1378797783168. Its totient is φ = 1028255969664.
The previous prime is 1203040012393. The next prime is 1203040012459. The reversal of 1203040012433 is 3342100403021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1203040012433 - 214 = 1203039996049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1203040012399 and 1203040012408.
It is not an unprimeable number, because it can be changed into a prime (1203040032433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 243429341 + ... + 243434282.
It is an arithmetic number, because the mean of its divisors is an integer number (172349722896).
Almost surely, 21203040012433 is an apocalyptic number.
It is an amenable number.
1203040012433 is a deficient number, since it is larger than the sum of its proper divisors (175757770735).
1203040012433 is an equidigital number, since it uses as much as digits as its factorization.
1203040012433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 486863983.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 1203040012433 its reverse (3342100403021), we get a palindrome (4545140415454).
The spelling of 1203040012433 in words is "one trillion, two hundred three billion, forty million, twelve thousand, four hundred thirty-three".
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