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12031113122010 = 232523263172112841
BaseRepresentation
bin1010111100010011011000…
…1110010101000011011010
31120121011101221220110111200
42233010312032111003122
53034104204424401020
641331003404135030
72351135125126023
oct257046616250332
946534357813450
1012031113122010
113919403785984
121423863537476
136936b557b258
142d8447bbdc4a
1515ce54623590
hexaf1363950da

12031113122010 has 192 divisors, whose sum is σ = 32786634456576. Its totient is φ = 3055122892800.

The previous prime is 12031113122009. The next prime is 12031113122057. The reversal of 12031113122010 is 1022131113021.

12031113122010 is a `hidden beast` number, since 1 + 2 + 0 + 311 + 131 + 220 + 1 + 0 = 666.

12031113122010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 936923190 + ... + 936936030.

It is an arithmetic number, because the mean of its divisors is an integer number (170763721128).

Almost surely, 212031113122010 is an apocalyptic number.

12031113122010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 12031113122010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16393317228288).

12031113122010 is an abundant number, since it is smaller than the sum of its proper divisors (20755521334566).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12031113122010 is a wasteful number, since it uses less digits than its factorization.

12031113122010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14861 (or 14858 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 12031113122010 its reverse (1022131113021), we get a palindrome (13053244235031).

It can be divided in two parts, 120311 and 13122010, that added together give a square (13242321 = 36392).

The spelling of 12031113122010 in words is "twelve trillion, thirty-one billion, one hundred thirteen million, one hundred twenty-two thousand, ten".