Base | Representation |
---|---|
bin | 111000000001100011… |
… | …1001100000000000111 |
3 | 102111112200221021221220 |
4 | 1300003013030000013 |
5 | 3432344143100403 |
6 | 131134212411423 |
7 | 11456266114611 |
oct | 1600307140007 |
9 | 374480837856 |
10 | 120311300103 |
11 | 47029657535 |
12 | 1b398016b73 |
13 | b464840707 |
14 | 5b7481bdb1 |
15 | 31e2497953 |
hex | 1c031cc007 |
120311300103 has 4 divisors (see below), whose sum is σ = 160415066808. Its totient is φ = 80207533400.
The previous prime is 120311300077. The next prime is 120311300107. The reversal of 120311300103 is 301003113021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120311300103 - 216 = 120311234567 is a prime.
It is a zygodrome in base 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120311300107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20051883348 + ... + 20051883353.
It is an arithmetic number, because the mean of its divisors is an integer number (40103766702).
Almost surely, 2120311300103 is an apocalyptic number.
120311300103 is a deficient number, since it is larger than the sum of its proper divisors (40103766705).
120311300103 is an equidigital number, since it uses as much as digits as its factorization.
120311300103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40103766704.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 120311300103 its reverse (301003113021), we get a palindrome (421314413124).
The spelling of 120311300103 in words is "one hundred twenty billion, three hundred eleven million, three hundred thousand, one hundred three".
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