120313130033401 has 4 divisors (see below), whose sum is σ = 122007681160704. Its totient is φ = 118618578906100.

The previous prime is 120313130033333. The next prime is 120313130033461. The reversal of 120313130033401 is 104330031313021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120313130033401 is a prime.

It is a super-2 number, since 2×120313130033401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120313130033461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 847275563545 + ... + 847275563686.

It is an arithmetic number, because the mean of its divisors is an integer number (30501920290176).

Almost surely, 2^{120313130033401} is an apocalyptic number.

It is an amenable number.

120313130033401 is a deficient number, since it is larger than the sum of its proper divisors (1694551127303).

120313130033401 is an equidigital number, since it uses as much as digits as its factorization.

120313130033401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1694551127302.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 120313130033401 its reverse (104330031313021), we get a palindrome (224643161346422).

The spelling of 120313130033401 in words is "one hundred twenty trillion, three hundred thirteen billion, one hundred thirty million, thirty-three thousand, four hundred one".