Base | Representation |
---|---|
bin | 10110011010001111… |
… | …10110100101000001 |
3 | 1011001111001111122120 |
4 | 23031013312211001 |
5 | 144120004304213 |
6 | 5305504554453 |
7 | 604101360534 |
oct | 131507664501 |
9 | 34044044576 |
10 | 12031322433 |
11 | 5114405689 |
12 | 23b9322a29 |
13 | 11997b0700 |
14 | 821c52a1b |
15 | 4a63ab423 |
hex | 2cd1f6941 |
12031322433 has 24 divisors (see below), whose sum is σ = 18392483808. Its totient is φ = 6968362752.
The previous prime is 12031322431. The next prime is 12031322473. The reversal of 12031322433 is 33422313021.
12031322433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12031322433 - 21 = 12031322431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12031322431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 689335 + ... + 706572.
It is an arithmetic number, because the mean of its divisors is an integer number (766353492).
Almost surely, 212031322433 is an apocalyptic number.
12031322433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12031322433 is a deficient number, since it is larger than the sum of its proper divisors (6361161375).
12031322433 is a wasteful number, since it uses less digits than its factorization.
12031322433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1395953 (or 1395940 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 12031322433 its reverse (33422313021), we get a palindrome (45453635454).
The spelling of 12031322433 in words is "twelve billion, thirty-one million, three hundred twenty-two thousand, four hundred thirty-three".
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