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12031431341 = 18719642739
BaseRepresentation
bin10110011010010000…
…10001001010101101
31011001111021001001012
423031020101022231
5144120021300331
65305511155005
7604102323206
oct131510211255
934044231035
1012031431341
11511447a496
1223b9375a65
13119981b157
14821c805ad
154a63cd82b
hex2cd2112ad

12031431341 has 4 divisors (see below), whose sum is σ = 12032092800. Its totient is φ = 12030769884.

The previous prime is 12031431329. The next prime is 12031431407. The reversal of 12031431341 is 14313413021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14313413021 = 21796568799.

It is a cyclic number.

It is not a de Polignac number, because 12031431341 - 218 = 12031169197 is a prime.

It is a super-2 number, since 2×120314313412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12034431341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302651 + ... + 340088.

It is an arithmetic number, because the mean of its divisors is an integer number (3008023200).

Almost surely, 212031431341 is an apocalyptic number.

It is an amenable number.

12031431341 is a deficient number, since it is larger than the sum of its proper divisors (661459).

12031431341 is an equidigital number, since it uses as much as digits as its factorization.

12031431341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 661458.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 12031431341 its reverse (14313413021), we get a palindrome (26344844362).

The spelling of 12031431341 in words is "twelve billion, thirty-one million, four hundred thirty-one thousand, three hundred forty-one".

Divisors: 1 18719 642739 12031431341