Search a number
-
+
120320130113 = 199323679249
BaseRepresentation
bin111000000001110100…
…0110111110001000001
3102111120022112220110022
41300003220313301001
53432403423130423
6131135125543225
711456434142231
oct1600350676101
9374508486408
10120320130113
1147033638667
121b39ab74b15
13b466612881
145b75a79cc1
1531e313ddc8
hex1c03a37c41

120320130113 has 8 divisors (see below), whose sum is σ = 126666540000. Its totient is φ = 113975097408.

The previous prime is 120320130103. The next prime is 120320130127. The reversal of 120320130113 is 311031023021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120320130113 - 210 = 120320129089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120320130091 and 120320130100.

It is not an unprimeable number, because it can be changed into a prime (120320130103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162488 + ... + 516761.

It is an arithmetic number, because the mean of its divisors is an integer number (15833317500).

Almost surely, 2120320130113 is an apocalyptic number.

It is an amenable number.

120320130113 is a deficient number, since it is larger than the sum of its proper divisors (6346409887).

120320130113 is an equidigital number, since it uses as much as digits as its factorization.

120320130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 688591.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 120320130113 its reverse (311031023021), we get a palindrome (431351153134).

The spelling of 120320130113 in words is "one hundred twenty billion, three hundred twenty million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 19 9323 177137 679249 12905731 6332638427 120320130113