Base | Representation |
---|---|
bin | 11101110100010001000110… |
… | …100100110101100100111001 |
3 | 122012022101200100222112100221 |
4 | 131310101012210311210321 |
5 | 114142004214114340400 |
6 | 1142522351153500041 |
7 | 36423125441501536 |
oct | 3564210644654471 |
9 | 565271610875327 |
10 | 131135125543225 |
11 | 38869104757791 |
12 | 1285aa48271621 |
13 | 5822cb259c15b |
14 | 2454d8c6d1d8d |
15 | 10261d3b27c1a |
hex | 774446935939 |
131135125543225 has 6 divisors (see below), whose sum is σ = 162607555673630. Its totient is φ = 104908100434560.
The previous prime is 131135125543211. The next prime is 131135125543309. The reversal of 131135125543225 is 522345521531131.
It can be written as a sum of positive squares in 3 ways, for example, as 25905443088121 + 105229682455104 = 5089739^2 + 10258152^2 .
It is not a de Polignac number, because 131135125543225 - 29 = 131135125542713 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2622702510840 + ... + 2622702510889.
Almost surely, 2131135125543225 is an apocalyptic number.
It is an amenable number.
131135125543225 is a deficient number, since it is larger than the sum of its proper divisors (31472430130405).
131135125543225 is an equidigital number, since it uses as much as digits as its factorization.
131135125543225 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5245405021739 (or 5245405021734 counting only the distinct ones).
The product of its digits is 540000, while the sum is 43.
The spelling of 131135125543225 in words is "one hundred thirty-one trillion, one hundred thirty-five billion, one hundred twenty-five million, five hundred forty-three thousand, two hundred twenty-five".
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