12032040351015 has 12 divisors (see below), whose sum is σ = 20855536608504. Its totient is φ = 6417088187184.

The previous prime is 12032040351011. The next prime is 12032040351017. The reversal of 12032040351015 is 51015304023021.

12032040351015 is a `hidden beast` number, since 1 + 203 + 2 + 0 + 403 + 51 + 0 + 1 + 5 = 666.

It is not a de Polignac number, because 12032040351015 - 2² = 12032040351011 is a prime.

It is a super-4 number, since 4×12032040351015⁴ (a number of 53 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12032040351015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12032040351011) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 133689337189 + ... + 133689337278.

It is an arithmetic number, because the mean of its divisors is an integer number (1737961384042).

Almost surely, 2^{12032040351015} is an apocalyptic number.

12032040351015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12032040351015 is a deficient number, since it is larger than the sum of its proper divisors (8823496257489).

12032040351015 is a wasteful number, since it uses less digits than its factorization.

12032040351015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267378674478 (or 267378674475 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 12032040351015 its reverse (51015304023021), we get a palindrome (63047344374036).

The spelling of 12032040351015 in words is "twelve trillion, thirty-two billion, forty million, three hundred fifty-one thousand, fifteen".