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12033113001103 = 67179598701509
BaseRepresentation
bin1010111100011010110101…
…1011010000110010001111
31120121100120100000211212201
42233012231123100302033
53034122303412013403
641331534044342331
72351235520615225
oct257065533206217
946540510024781
1012033113001103
11391a23a64a717
1214241212449a7
136939439b256c
142d8597646b15
1515d01eeb021d
hexaf1ad6d0c8f

12033113001103 has 4 divisors (see below), whose sum is σ = 12212711702680. Its totient is φ = 11853514299528.

The previous prime is 12033113001083. The next prime is 12033113001109. The reversal of 12033113001103 is 30110031133021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12033113001103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12033113001109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89799350688 + ... + 89799350821.

It is an arithmetic number, because the mean of its divisors is an integer number (3053177925670).

Almost surely, 212033113001103 is an apocalyptic number.

12033113001103 is a deficient number, since it is larger than the sum of its proper divisors (179598701577).

12033113001103 is an equidigital number, since it uses as much as digits as its factorization.

12033113001103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179598701576.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 12033113001103 its reverse (30110031133021), we get a palindrome (42143144134124).

The spelling of 12033113001103 in words is "twelve trillion, thirty-three billion, one hundred thirteen million, one thousand, one hundred three".

Divisors: 1 67 179598701509 12033113001103