Base | Representation |
---|---|
bin | 111000000010100000… |
… | …0000111010100000011 |
3 | 102111121220120211111010 |
4 | 1300011000013110003 |
5 | 3432430302002243 |
6 | 131141304052003 |
7 | 11460132424230 |
oct | 1600500072403 |
9 | 374556524433 |
10 | 120343000323 |
11 | 47045539367 |
12 | 1b3a6764003 |
13 | b46b28c540 |
14 | 5b78b10787 |
15 | 31e515a433 |
hex | 1c05007503 |
120343000323 has 64 divisors (see below), whose sum is σ = 211967788032. Its totient is φ = 58925076480.
The previous prime is 120343000319. The next prime is 120343000333. The reversal of 120343000323 is 323000343021.
It is not a de Polignac number, because 120343000323 - 22 = 120343000319 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 120343000323.
It is not an unprimeable number, because it can be changed into a prime (120343000333) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 161188 + ... + 516398.
It is an arithmetic number, because the mean of its divisors is an integer number (3311996688).
Almost surely, 2120343000323 is an apocalyptic number.
120343000323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120343000323 is a deficient number, since it is larger than the sum of its proper divisors (91624787709).
120343000323 is a wasteful number, since it uses less digits than its factorization.
120343000323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 355324.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 120343000323 its reverse (323000343021), we get a palindrome (443343343344).
The spelling of 120343000323 in words is "one hundred twenty billion, three hundred forty-three million, three hundred twenty-three", and thus it is an aban number.
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