Base | Representation |
---|---|
bin | 10001100001010100000… |
… | …001000111110011011011 |
3 | 11021002201212012122212010 |
4 | 101201110001013303123 |
5 | 124211243102020011 |
6 | 2321035443321003 |
7 | 152662152511152 |
oct | 21412401076333 |
9 | 4232655178763 |
10 | 1204000423131 |
11 | 42468293a210 |
12 | 175415380163 |
13 | 896c9326b9c |
14 | 423b994c599 |
15 | 214baee61a6 |
hex | 11854047cdb |
1204000423131 has 32 divisors (see below), whose sum is σ = 1755710208000. Its totient is φ = 727849543680.
The previous prime is 1204000423127. The next prime is 1204000423133. The reversal of 1204000423131 is 1313240004021.
It is not a de Polignac number, because 1204000423131 - 22 = 1204000423127 is a prime.
It is a super-2 number, since 2×12040004231312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1204000423098 and 1204000423107.
It is not an unprimeable number, because it can be changed into a prime (1204000423133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 57435030 + ... + 57455988.
It is an arithmetic number, because the mean of its divisors is an integer number (54865944000).
Almost surely, 21204000423131 is an apocalyptic number.
1204000423131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1204000423131 is a deficient number, since it is larger than the sum of its proper divisors (551709784869).
1204000423131 is a wasteful number, since it uses less digits than its factorization.
1204000423131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25299.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 1204000423131 its reverse (1313240004021), we get a palindrome (2517240427152).
The spelling of 1204000423131 in words is "one trillion, two hundred four billion, four hundred twenty-three thousand, one hundred thirty-one".
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