1204040121 has 4 divisors (see below), whose sum is σ = 1605386832. Its totient is φ = 802693412.

The previous prime is 1204040111. The next prime is 1204040141. The reversal of 1204040121 is 1210404021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1204040121 - 2¹³ = 1204031929 is a prime.

It is a super-2 number, since 2×1204040121² = 2899425225955389282, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1204040121.

It is not an unprimeable number, because it can be changed into a prime (1204040111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200673351 + ... + 200673356.

It is an arithmetic number, because the mean of its divisors is an integer number (401346708).

Almost surely, 2^1204040121 is an apocalyptic number.

It is an amenable number.

1204040121 is a deficient number, since it is larger than the sum of its proper divisors (401346711).

1204040121 is an equidigital number, since it uses as much as digits as its factorization.

1204040121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 401346710.

The product of its (nonzero) digits is 64, while the sum is 15.

The square root of 1204040121 is about 34699.2812749774. The cubic root of 1204040121 is about 1063.8498080844.

Adding to 1204040121 its reverse (1210404021), we get a palindrome (2414444142).

The spelling of 1204040121 in words is "one billion, two hundred four million, forty thousand, one hundred twenty-one".