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12041045551 = 70916983139
BaseRepresentation
bin10110011011011001…
…11100011000101111
31011002011100111021001
423031230330120233
5144130001424201
65310453221131
7604250125033
oct131554743057
934064314231
1012041045551
115119946817
1224006317a7
13119b806232
148232641c3
154a717c301
hex2cdb3c62f

12041045551 has 4 divisors (see below), whose sum is σ = 12058029400. Its totient is φ = 12024061704.

The previous prime is 12041045539. The next prime is 12041045557. The reversal of 12041045551 is 15554014021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12041045551 - 211 = 12041043503 is a prime.

It is a super-2 number, since 2×120410455512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12041045557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8490861 + ... + 8492278.

It is an arithmetic number, because the mean of its divisors is an integer number (3014507350).

Almost surely, 212041045551 is an apocalyptic number.

12041045551 is a deficient number, since it is larger than the sum of its proper divisors (16983849).

12041045551 is an equidigital number, since it uses as much as digits as its factorization.

12041045551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16983848.

The product of its (nonzero) digits is 4000, while the sum is 28.

Adding to 12041045551 its reverse (15554014021), we get a palindrome (27595059572).

The spelling of 12041045551 in words is "twelve billion, forty-one million, forty-five thousand, five hundred fifty-one".

Divisors: 1 709 16983139 12041045551