12041130133423 has 4 divisors (see below), whose sum is σ = 12076860490240. Its totient is φ = 12005399776608.

The previous prime is 12041130133399. The next prime is 12041130133441. The reversal of 12041130133423 is 32433103114021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12041130133423 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12041130133391 and 12041130133400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12041130133463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17865177903 + ... + 17865178576.

It is an arithmetic number, because the mean of its divisors is an integer number (3019215122560).

Almost surely, 2^{12041130133423} is an apocalyptic number.

12041130133423 is a deficient number, since it is larger than the sum of its proper divisors (35730356817).

12041130133423 is an equidigital number, since it uses as much as digits as its factorization.

12041130133423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35730356816.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 12041130133423 its reverse (32433103114021), we get a palindrome (44474233247444).

The spelling of 12041130133423 in words is "twelve trillion, forty-one billion, one hundred thirty million, one hundred thirty-three thousand, four hundred twenty-three".