Base | Representation |
---|---|
bin | 10110011011011011… |
… | …00101100000111011 |
3 | 1011002011200001100022 |
4 | 23031231211200323 |
5 | 144130022322021 |
6 | 5310501001055 |
7 | 604251426131 |
oct | 131555454073 |
9 | 34064601308 |
10 | 12041214011 |
11 | 5119a51342 |
12 | 24006b318b |
13 | 119b864b08 |
14 | 8232a9751 |
15 | 4a71b21ab |
hex | 2cdb6583b |
12041214011 has 4 divisors (see below), whose sum is σ = 12238611024. Its totient is φ = 11843817000.
The previous prime is 12041213993. The next prime is 12041214013. The reversal of 12041214011 is 11041214021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11041214021 = 1993 ⋅5539997.
It is a cyclic number.
It is not a de Polignac number, because 12041214011 - 226 = 11974105147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12041214013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98698415 + ... + 98698536.
It is an arithmetic number, because the mean of its divisors is an integer number (3059652756).
Almost surely, 212041214011 is an apocalyptic number.
12041214011 is a deficient number, since it is larger than the sum of its proper divisors (197397013).
12041214011 is an equidigital number, since it uses as much as digits as its factorization.
12041214011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197397012.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 12041214011 its reverse (11041214021), we get a palindrome (23082428032).
The spelling of 12041214011 in words is "twelve billion, forty-one million, two hundred fourteen thousand, eleven".
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