Base | Representation |
---|---|
bin | 1010111100111001110000… |
… | …0101111011100010111010 |
3 | 1120122010222201022022212011 |
4 | 2233032130011323202322 |
5 | 3034241303001143002 |
6 | 41335425351440134 |
7 | 2351651263222222 |
oct | 257163405734272 |
9 | 46563881268764 |
10 | 12041412131002 |
11 | 3922809257861 |
12 | 142585868604a |
13 | 6946671aa407 |
14 | 2d8b43939082 |
15 | 15d3588968d7 |
hex | af39c17b8ba |
12041412131002 has 4 divisors (see below), whose sum is σ = 18062118196506. Its totient is φ = 6020706065500.
The previous prime is 12041412130963. The next prime is 12041412131003. The reversal of 12041412131002 is 20013121414021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10163720187481 + 1877691943521 = 3188059^2 + 1370289^2 .
It is a super-2 number, since 2×120414121310022 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12041412131003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3010353032749 + ... + 3010353032752.
Almost surely, 212041412131002 is an apocalyptic number.
12041412131002 is a deficient number, since it is larger than the sum of its proper divisors (6020706065504).
12041412131002 is an equidigital number, since it uses as much as digits as its factorization.
12041412131002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6020706065503.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12041412131002 its reverse (20013121414021), we get a palindrome (32054533545023).
The spelling of 12041412131002 in words is "twelve trillion, forty-one billion, four hundred twelve million, one hundred thirty-one thousand, two".
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