Base | Representation |
---|---|
bin | 11011011000100010001010… |
… | …000111100101011100010111 |
3 | 120210102022010210102112101001 |
4 | 123120202022013211130113 |
5 | 111241134143224132043 |
6 | 1104050125353044131 |
7 | 34240003654266211 |
oct | 3330421207453427 |
9 | 523368123375331 |
10 | 120433200224023 |
11 | 35412484926285 |
12 | 116109170b6647 |
13 | 5227a5714988b |
14 | 21a4dd86c35b1 |
15 | ddcb25abc74d |
hex | 6d888a1e5717 |
120433200224023 has 8 divisors (see below), whose sum is σ = 121154642606592. Its totient is φ = 119711761240536.
The previous prime is 120433200224009. The next prime is 120433200224033. The reversal of 120433200224023 is 320422002334021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120433200224023 - 225 = 120433166669591 is a prime.
It is a super-3 number, since 3×1204332002240233 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120433200223982 and 120433200224000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120433200224033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 136702486 + ... + 137580652.
It is an arithmetic number, because the mean of its divisors is an integer number (15144330325824).
Almost surely, 2120433200224023 is an apocalyptic number.
120433200224023 is a deficient number, since it is larger than the sum of its proper divisors (721442382569).
120433200224023 is an equidigital number, since it uses as much as digits as its factorization.
120433200224023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1699541.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 120433200224023 its reverse (320422002334021), we get a palindrome (440855202558044).
The spelling of 120433200224023 in words is "one hundred twenty trillion, four hundred thirty-three billion, two hundred million, two hundred twenty-four thousand, twenty-three".
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