12043330441 has 4 divisors (see below), whose sum is σ = 12074775552. Its totient is φ = 12011885332.

The previous prime is 12043330433. The next prime is 12043330457. The reversal of 12043330441 is 14403334021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12043330441 - 2³ = 12043330433 is a prime.

It is a super-2 number, since 2×12043330441² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12043330241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15721981 + ... + 15722746.

It is an arithmetic number, because the mean of its divisors is an integer number (3018693888).

Almost surely, 2^12043330441 is an apocalyptic number.

It is an amenable number.

12043330441 is a deficient number, since it is larger than the sum of its proper divisors (31445111).

12043330441 is an equidigital number, since it uses as much as digits as its factorization.

12043330441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31445110.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 12043330441 its reverse (14403334021), we get a palindrome (26446664462).

The spelling of 12043330441 in words is "twelve billion, forty-three million, three hundred thirty thousand, four hundred forty-one".