12043343311441 has 12 divisors (see below), whose sum is σ = 12989411559516. Its totient is φ = 11100108697920.

The previous prime is 12043343311429. The next prime is 12043343311463. The reversal of 12043343311441 is 14411334334021.

It can be written as a sum of positive squares in 6 ways, for example, as 25362155025 + 12017981156416 = 159255^2 + 3466696^2 .

It is not a de Polignac number, because 12043343311441 - 2¹⁷ = 12043343180369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12043343311397 and 12043343311406.

It is not an unprimeable number, because it can be changed into a prime (12043343311471) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4619815 + ... + 6740131.

It is an arithmetic number, because the mean of its divisors is an integer number (1082450963293).

Almost surely, 2^{12043343311441} is an apocalyptic number.

It is an amenable number.

12043343311441 is a deficient number, since it is larger than the sum of its proper divisors (946068248075).

12043343311441 is an frugal number, since it uses more digits than its factorization.

12043343311441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2121652 (or 2120991 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 12043343311441 its reverse (14411334334021), we get a palindrome (26454677645462).

The spelling of 12043343311441 in words is "twelve trillion, forty-three billion, three hundred forty-three million, three hundred eleven thousand, four hundred forty-one".