Base | Representation |
---|---|
bin | 1010111101000001001100… |
… | …0110101010110001010111 |
3 | 1120122100010212102021211120 |
4 | 2233100103012222301113 |
5 | 3034304400124010033 |
6 | 41340355435335023 |
7 | 2352051616565031 |
oct | 257202306526127 |
9 | 46570125367746 |
10 | 12043408813143 |
11 | 3923643338694 |
12 | 14261152b1473 |
13 | 6948c4a62536 |
14 | 2d8c92bacc51 |
15 | 15d423d011b3 |
hex | af4131aac57 |
12043408813143 has 16 divisors (see below), whose sum is σ = 16321638904800. Its totient is φ = 7897067297280.
The previous prime is 12043408813091. The next prime is 12043408813181. The reversal of 12043408813143 is 34131880434021.
12043408813143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12043408813143 - 210 = 12043408812119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12043408813095 and 12043408813104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12043408813043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4846843 + ... + 6897731.
It is an arithmetic number, because the mean of its divisors is an integer number (1020102431550).
Almost surely, 212043408813143 is an apocalyptic number.
12043408813143 is a deficient number, since it is larger than the sum of its proper divisors (4278230091657).
12043408813143 is a wasteful number, since it uses less digits than its factorization.
12043408813143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2083042.
The product of its (nonzero) digits is 221184, while the sum is 42.
The spelling of 12043408813143 in words is "twelve trillion, forty-three billion, four hundred eight million, eight hundred thirteen thousand, one hundred forty-three".
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