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1204430001141 = 33710850720731
BaseRepresentation
bin10001100001101101100…
…111110101001111110101
311021010211210112111002210
4101201231213311033311
5124213133040014031
62321150230524033
7153005620043163
oct21415547651765
94233753474083
101204430001141
11424883377564
12175515206619
1389767323363
144241aa12233
15214e3a9d746
hex1186d9f53f5

1204430001141 has 8 divisors (see below), whose sum is σ = 1649309551264. Its totient is φ = 781251892560.

The previous prime is 1204430001113. The next prime is 1204430001199. The reversal of 1204430001141 is 1411000344021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1204430001141 - 25 = 1204430001109 is a prime.

It is a super-2 number, since 2×12044300011412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1204430001041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5425360255 + ... + 5425360476.

It is an arithmetic number, because the mean of its divisors is an integer number (206163693908).

Almost surely, 21204430001141 is an apocalyptic number.

It is an amenable number.

1204430001141 is a deficient number, since it is larger than the sum of its proper divisors (444879550123).

1204430001141 is a wasteful number, since it uses less digits than its factorization.

1204430001141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10850720771.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1204430001141 its reverse (1411000344021), we get a palindrome (2615430345162).

The spelling of 1204430001141 in words is "one trillion, two hundred four billion, four hundred thirty million, one thousand, one hundred forty-one".

Divisors: 1 3 37 111 10850720731 32552162193 401476667047 1204430001141