120444335133113 has 4 divisors (see below), whose sum is σ = 120485824745088. Its totient is φ = 120402845521140.

The previous prime is 120444335133091. The next prime is 120444335133119. The reversal of 120444335133113 is 311331533444021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120444335133113 - 2⁶ = 120444335133049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120444335133119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20744801633 + ... + 20744807438.

It is an arithmetic number, because the mean of its divisors is an integer number (30121456186272).

Almost surely, 2^{120444335133113} is an apocalyptic number.

It is an amenable number.

120444335133113 is a deficient number, since it is larger than the sum of its proper divisors (41489611975).

120444335133113 is an equidigital number, since it uses as much as digits as its factorization.

120444335133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41489611974.

The product of its (nonzero) digits is 155520, while the sum is 38.

Adding to 120444335133113 its reverse (311331533444021), we get a palindrome (431775868577134).

The spelling of 120444335133113 in words is "one hundred twenty trillion, four hundred forty-four billion, three hundred thirty-five million, one hundred thirty-three thousand, one hundred thirteen".