Search a number
-
+
12050212111151 = 43280237490957
BaseRepresentation
bin1010111101011010100010…
…0111001100001100101111
31120122222201000000122012212
42233112220213030030233
53034412313300024101
641343442505521035
72352412326634064
oct257265047141457
946588630018185
1012050212111151
113926514652125
1214274b37a317b
1369543a397366
142d933a564c6b
1515d6c12131bb
hexaf5a89cc32f

12050212111151 has 4 divisors (see below), whose sum is σ = 12330449602152. Its totient is φ = 11769974620152.

The previous prime is 12050212111111. The next prime is 12050212111181. The reversal of 12050212111151 is 15111121205021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12050212111151 - 26 = 12050212111087 is a prime.

It is a super-2 number, since 2×120502121111512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12050212111111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140118745436 + ... + 140118745521.

It is an arithmetic number, because the mean of its divisors is an integer number (3082612400538).

Almost surely, 212050212111151 is an apocalyptic number.

12050212111151 is a deficient number, since it is larger than the sum of its proper divisors (280237491001).

12050212111151 is an equidigital number, since it uses as much as digits as its factorization.

12050212111151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280237491000.

The product of its (nonzero) digits is 200, while the sum is 23.

Adding to 12050212111151 its reverse (15111121205021), we get a palindrome (27161333316172).

The spelling of 12050212111151 in words is "twelve trillion, fifty billion, two hundred twelve million, one hundred eleven thousand, one hundred fifty-one".

Divisors: 1 43 280237490957 12050212111151