Base | Representation |
---|---|
bin | 1010111101011010100010… |
… | …0111001100001100101111 |
3 | 1120122222201000000122012212 |
4 | 2233112220213030030233 |
5 | 3034412313300024101 |
6 | 41343442505521035 |
7 | 2352412326634064 |
oct | 257265047141457 |
9 | 46588630018185 |
10 | 12050212111151 |
11 | 3926514652125 |
12 | 14274b37a317b |
13 | 69543a397366 |
14 | 2d933a564c6b |
15 | 15d6c12131bb |
hex | af5a89cc32f |
12050212111151 has 4 divisors (see below), whose sum is σ = 12330449602152. Its totient is φ = 11769974620152.
The previous prime is 12050212111111. The next prime is 12050212111181. The reversal of 12050212111151 is 15111121205021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12050212111151 - 26 = 12050212111087 is a prime.
It is a super-2 number, since 2×120502121111512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12050212111111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140118745436 + ... + 140118745521.
It is an arithmetic number, because the mean of its divisors is an integer number (3082612400538).
Almost surely, 212050212111151 is an apocalyptic number.
12050212111151 is a deficient number, since it is larger than the sum of its proper divisors (280237491001).
12050212111151 is an equidigital number, since it uses as much as digits as its factorization.
12050212111151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280237491000.
The product of its (nonzero) digits is 200, while the sum is 23.
Adding to 12050212111151 its reverse (15111121205021), we get a palindrome (27161333316172).
The spelling of 12050212111151 in words is "twelve trillion, fifty billion, two hundred twelve million, one hundred eleven thousand, one hundred fifty-one".
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