Base | Representation |
---|---|
bin | 1010111101100001010010… |
… | …1101001101111001111111 |
3 | 1120200011101101110221212001 |
4 | 2233120110231031321333 |
5 | 3034430022030132320 |
6 | 41344342451523131 |
7 | 2352505300406035 |
oct | 257302455157177 |
9 | 46604341427761 |
10 | 12052025630335 |
11 | 39272652aaa09 |
12 | 142791abb94a7 |
13 | 69566900ba32 |
14 | 2d946d35a555 |
15 | 15d77a53c20a |
hex | af614b4de7f |
12052025630335 has 4 divisors (see below), whose sum is σ = 14462430756408. Its totient is φ = 9641620504264.
The previous prime is 12052025630287. The next prime is 12052025630347. The reversal of 12052025630335 is 53303652025021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12052025630335 - 215 = 12052025597567 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12052025630294 and 12052025630303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1205202563029 + ... + 1205202563038.
It is an arithmetic number, because the mean of its divisors is an integer number (3615607689102).
Almost surely, 212052025630335 is an apocalyptic number.
12052025630335 is a deficient number, since it is larger than the sum of its proper divisors (2410405126073).
12052025630335 is an equidigital number, since it uses as much as digits as its factorization.
12052025630335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2410405126072.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 12052025630335 its reverse (53303652025021), we get a palindrome (65355677655356).
The spelling of 12052025630335 in words is "twelve trillion, fifty-two billion, twenty-five million, six hundred thirty thousand, three hundred thirty-five".
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