12056843303 has 4 divisors (see below), whose sum is σ = 12057456888. Its totient is φ = 12056229720.

The previous prime is 12056843287. The next prime is 12056843311. The reversal of 12056843303 is 30334865021.

12056843303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12056843303 - 2⁴ = 12056843287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12056803303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276308 + ... + 316953.

It is an arithmetic number, because the mean of its divisors is an integer number (3014364222).

Almost surely, 2^12056843303 is an apocalyptic number.

12056843303 is a deficient number, since it is larger than the sum of its proper divisors (613585).

12056843303 is an equidigital number, since it uses as much as digits as its factorization.

12056843303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 613584.

The product of its (nonzero) digits is 51840, while the sum is 35.

The spelling of 12056843303 in words is "twelve billion, fifty-six million, eight hundred forty-three thousand, three hundred three".