12057433 has 4 divisors (see below), whose sum is σ = 12227328. Its totient is φ = 11887540.

The previous prime is 12057431. The next prime is 12057467. The reversal of 12057433 is 33475021.

12057433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33475021 = 257 ⋅130253.

It is a cyclic number.

It is not a de Polignac number, because 12057433 - 2¹ = 12057431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12057398 and 12057407.

It is not an unprimeable number, because it can be changed into a prime (12057431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84841 + ... + 84982.

It is an arithmetic number, because the mean of its divisors is an integer number (3056832).

Almost surely, 2^12057433 is an apocalyptic number.

It is an amenable number.

12057433 is a deficient number, since it is larger than the sum of its proper divisors (169895).

12057433 is an equidigital number, since it uses as much as digits as its factorization.

12057433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169894.

The product of its (nonzero) digits is 2520, while the sum is 25.

The square root of 12057433 is about 3472.3814594598. The cubic root of 12057433 is about 229.3075138722.

The spelling of 12057433 in words is "twelve million, fifty-seven thousand, four hundred thirty-three".