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12100111011120 = 24351129244164747
BaseRepresentation
bin1011000000010100011011…
…0100011000110100110000
31120211202111112121101200010
42300011012310120310300
53041222011404323440
641422414140254520
72356130013403416
oct260050664306460
946752445541603
1012100111011120
1139456a0242230
1214350ba841440
1369a0601c9982
142db9116992b6
1515eb41c87580
hexb0146d18d30

12100111011120 has 320 divisors, whose sum is σ = 42349418749440. Its totient is φ = 2831005900800.

The previous prime is 12100111011097. The next prime is 12100111011143. The reversal of 12100111011120 is 2111011100121.

It is an interprime number because it is at equal distance from previous prime (12100111011097) and next prime (12100111011143).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 12100111011096 and 12100111011105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 186850587 + ... + 186915333.

It is an arithmetic number, because the mean of its divisors is an integer number (132341933592).

Almost surely, 212100111011120 is an apocalyptic number.

12100111011120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12100111011120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21174709374720).

12100111011120 is an abundant number, since it is smaller than the sum of its proper divisors (30249307738320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12100111011120 is a wasteful number, since it uses less digits than its factorization.

12100111011120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67244 (or 67238 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 12.

Adding to 12100111011120 its reverse (2111011100121), we get a palindrome (14211122111241).

It can be divided in two parts, 121001 and 11011120, that added together give a triangular number (11132121 = T4718).

The spelling of 12100111011120 in words is "twelve trillion, one hundred billion, one hundred eleven million, eleven thousand, one hundred twenty".