1210012001113 has 4 divisors (see below), whose sum is σ = 1210014224848. Its totient is φ = 1210009777380.

The previous prime is 1210012001089. The next prime is 1210012001131. The reversal of 1210012001113 is 3111002100121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1210012001113 - 2¹³ = 1210011992921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1210012001093 and 1210012001102.

It is not an unprimeable number, because it can be changed into a prime (1210012001213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312970 + ... + 1586812.

It is an arithmetic number, because the mean of its divisors is an integer number (302503556212).

Almost surely, 2^{1210012001113} is an apocalyptic number.

It is an amenable number.

1210012001113 is a deficient number, since it is larger than the sum of its proper divisors (2223735).

1210012001113 is an equidigital number, since it uses as much as digits as its factorization.

1210012001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2223734.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1210012001113 its reverse (3111002100121), we get a palindrome (4321014101234).

The spelling of 1210012001113 in words is "one trillion, two hundred ten billion, twelve million, one thousand, one hundred thirteen".