Base | Representation |
---|---|
bin | 1110011011001… |
… | …01010111011001 |
3 | 22102200111202120 |
4 | 13031211113121 |
5 | 221434021213 |
6 | 20001251453 |
7 | 2666331600 |
oct | 715452731 |
9 | 272614676 |
10 | 121001433 |
11 | 62336193 |
12 | 34633b89 |
13 | 1c0b79a7 |
14 | 120daa37 |
15 | a952423 |
hex | 73655d9 |
121001433 has 24 divisors (see below), whose sum is σ = 192756672. Its totient is φ = 67271904.
The previous prime is 121001431. The next prime is 121001437. The reversal of 121001433 is 334100121.
It is not a de Polignac number, because 121001433 - 21 = 121001431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121001431) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5685 + ... + 16562.
It is an arithmetic number, because the mean of its divisors is an integer number (8031528).
Almost surely, 2121001433 is an apocalyptic number.
It is an amenable number.
121001433 is a deficient number, since it is larger than the sum of its proper divisors (71755239).
121001433 is a wasteful number, since it uses less digits than its factorization.
121001433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22301 (or 22294 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 121001433 is about 11000.0651361708. The cubic root of 121001433 is about 494.6106968635.
Adding to 121001433 its reverse (334100121), we get a palindrome (455101554).
The spelling of 121001433 in words is "one hundred twenty-one million, one thousand, four hundred thirty-three".
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