121002112113 has 4 divisors (see below), whose sum is σ = 161336149488. Its totient is φ = 80668074740.

The previous prime is 121002112097. The next prime is 121002112129. The reversal of 121002112113 is 311211200121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (121002112097) and next prime (121002112129).

It is a cyclic number.

It is not a de Polignac number, because 121002112113 - 2⁴ = 121002112097 is a prime.

It is a super-2 number, since 2×121002112113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121002112092 and 121002112101.

It is not an unprimeable number, because it can be changed into a prime (121002112193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20167018683 + ... + 20167018688.

It is an arithmetic number, because the mean of its divisors is an integer number (40334037372).

Almost surely, 2^121002112113 is an apocalyptic number.

It is an amenable number.

121002112113 is a deficient number, since it is larger than the sum of its proper divisors (40334037375).

121002112113 is an equidigital number, since it uses as much as digits as its factorization.

121002112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40334037374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 121002112113 its reverse (311211200121), we get a palindrome (432213312234).

The spelling of 121002112113 in words is "one hundred twenty-one billion, two million, one hundred twelve thousand, one hundred thirteen".