Base | Representation |
---|---|
bin | 11011100000110100000000… |
… | …011111111011011011100111 |
3 | 120212102200121221010020022220 |
4 | 123200310000133323123213 |
5 | 111324444321213000403 |
6 | 1105203335113123423 |
7 | 34326054245506341 |
oct | 3340640037733347 |
9 | 525380557106286 |
10 | 121002122000103 |
11 | 356117913941a3 |
12 | 116a30319b9573 |
13 | 52695b3216c76 |
14 | 21c476924c291 |
15 | dec82232c953 |
hex | 6e0d007fb6e7 |
121002122000103 has 16 divisors (see below), whose sum is σ = 170827707937536. Its totient is φ = 75922374407040.
The previous prime is 121002122000101. The next prime is 121002122000113. The reversal of 121002122000103 is 301000221200121.
It is not a de Polignac number, because 121002122000103 - 21 = 121002122000101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121002122000101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 708883 + ... + 15572628.
It is an arithmetic number, because the mean of its divisors is an integer number (10676731746096).
Almost surely, 2121002122000103 is an apocalyptic number.
121002122000103 is a deficient number, since it is larger than the sum of its proper divisors (49825585937433).
121002122000103 is a wasteful number, since it uses less digits than its factorization.
121002122000103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16427254.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 121002122000103 its reverse (301000221200121), we get a palindrome (422002343200224).
The spelling of 121002122000103 in words is "one hundred twenty-one trillion, two billion, one hundred twenty-two million, one hundred three", and thus it is an aban number.
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