12100214113 has 8 divisors (see below), whose sum is σ = 13032788328. Its totient is φ = 11167895424.

The previous prime is 12100214111. The next prime is 12100214149. The reversal of 12100214113 is 31141200121.

12100214113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 177102864 + 11923111249 = 13308^2 + 109193^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12100214113 - 2¹ = 12100214111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12100214111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40845 + ... + 160837.

It is an arithmetic number, because the mean of its divisors is an integer number (1629098541).

Almost surely, 2^12100214113 is an apocalyptic number.

12100214113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12100214113 is a deficient number, since it is larger than the sum of its proper divisors (932574215).

12100214113 is a wasteful number, since it uses less digits than its factorization.

12100214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127763.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12100214113 its reverse (31141200121), we get a palindrome (43241414234).

The spelling of 12100214113 in words is "twelve billion, one hundred million, two hundred fourteen thousand, one hundred thirteen".