121004444131 has 8 divisors (see below), whose sum is σ = 125202181680. Its totient is φ = 116808384672.

The previous prime is 121004444123. The next prime is 121004444207. The reversal of 121004444131 is 131444400121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121004444131 - 2³ = 121004444123 is a prime.

It is a super-2 number, since 2×121004444131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121004444096 and 121004444105.

It is not an unprimeable number, because it can be changed into a prime (121004444731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 271920 + ... + 562093.

It is an arithmetic number, because the mean of its divisors is an integer number (15650272710).

Almost surely, 2^121004444131 is an apocalyptic number.

121004444131 is a deficient number, since it is larger than the sum of its proper divisors (4197737549).

121004444131 is an equidigital number, since it uses as much as digits as its factorization.

121004444131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 839045.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 121004444131 its reverse (131444400121), we get a palindrome (252448844252).

The spelling of 121004444131 in words is "one hundred twenty-one billion, four million, four hundred forty-four thousand, one hundred thirty-one".