Search a number
-
+
12100513141 = 23526109267
BaseRepresentation
bin10110100010011111…
…10010110101110101
31011020022020202110101
423101033302311311
5144240212410031
65320415554101
7605601443653
oct132117626565
934208222411
1012100513141
11514a473692
12241852b931
1311aac27a62
1482b103dd3
154ac4c7361
hex2d13f2d75

12100513141 has 4 divisors (see below), whose sum is σ = 12626622432. Its totient is φ = 11574403852.

The previous prime is 12100513133. The next prime is 12100513153. The reversal of 12100513141 is 14131500121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12100513141 - 23 = 12100513133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12100513111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263054611 + ... + 263054656.

It is an arithmetic number, because the mean of its divisors is an integer number (3156655608).

Almost surely, 212100513141 is an apocalyptic number.

It is an amenable number.

12100513141 is a deficient number, since it is larger than the sum of its proper divisors (526109291).

12100513141 is an equidigital number, since it uses as much as digits as its factorization.

12100513141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 526109290.

The product of its (nonzero) digits is 120, while the sum is 19.

The spelling of 12100513141 in words is "twelve billion, one hundred million, five hundred thirteen thousand, one hundred forty-one".

Divisors: 1 23 526109267 12100513141