Search a number
-
+
121006117151 = 412951368711
BaseRepresentation
bin111000010110010000…
…1101101000100011111
3102120100010100122202122
41300230201231010133
53440310031222101
6131331153013155
711512434011363
oct1605441550437
9376303318678
10121006117151
11473558868a7
121b5508541bb
13b54578696a
145bdcc072a3
15323349451b
hex1c2c86d11f

121006117151 has 4 divisors (see below), whose sum is σ = 123957485904. Its totient is φ = 118054748400.

The previous prime is 121006117117. The next prime is 121006117159. The reversal of 121006117151 is 151711600121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121006117151 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121006117151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121006117159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1475684315 + ... + 1475684396.

It is an arithmetic number, because the mean of its divisors is an integer number (30989371476).

Almost surely, 2121006117151 is an apocalyptic number.

121006117151 is a deficient number, since it is larger than the sum of its proper divisors (2951368753).

121006117151 is an equidigital number, since it uses as much as digits as its factorization.

121006117151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2951368752.

The product of its (nonzero) digits is 420, while the sum is 26.

Adding to 121006117151 its reverse (151711600121), we get a palindrome (272717717272).

The spelling of 121006117151 in words is "one hundred twenty-one billion, six million, one hundred seventeen thousand, one hundred fifty-one".

Divisors: 1 41 2951368711 121006117151