Base | Representation |
---|---|
bin | 10001100110111111101… |
… | …010000111101111111111 |
3 | 11021200111001002022212221 |
4 | 101212333222013233333 |
5 | 124311241413101343 |
6 | 2323525102310211 |
7 | 153266303223634 |
oct | 21467752075777 |
9 | 4250431068787 |
10 | 1210101300223 |
11 | 4272237004a2 |
12 | 176638588367 |
13 | 8a15c28272a |
14 | 427d7cda18b |
15 | 217269085ed |
hex | 119bfa87bff |
1210101300223 has 16 divisors (see below), whose sum is σ = 1275044738400. Its totient is φ = 1145283788160.
The previous prime is 1210101300197. The next prime is 1210101300241. The reversal of 1210101300223 is 3220031010121.
It is a cyclic number.
It is not a de Polignac number, because 1210101300223 - 233 = 1201511365631 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1210101300197 and 1210101300206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1210101300923) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 147192253 + ... + 147200473.
It is an arithmetic number, because the mean of its divisors is an integer number (79690296150).
Almost surely, 21210101300223 is an apocalyptic number.
1210101300223 is a deficient number, since it is larger than the sum of its proper divisors (64943438177).
1210101300223 is a wasteful number, since it uses less digits than its factorization.
1210101300223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14922.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1210101300223 its reverse (3220031010121), we get a palindrome (4430132310344).
The spelling of 1210101300223 in words is "one trillion, two hundred ten billion, one hundred one million, three hundred thousand, two hundred twenty-three".
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