12101033320033 has 8 divisors (see below), whose sum is σ = 13831114849920. Its totient is φ = 10371292411200.

The previous prime is 12101033319979. The next prime is 12101033320037. The reversal of 12101033320033 is 33002333010121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12101033320033 - 2¹³ = 12101033311841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12101033319986 and 12101033320013.

It is not an unprimeable number, because it can be changed into a prime (12101033320037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85079128 + ... + 85221241.

It is an arithmetic number, because the mean of its divisors is an integer number (1728889356240).

Almost surely, 2^{12101033320033} is an apocalyptic number.

It is an amenable number.

12101033320033 is a deficient number, since it is larger than the sum of its proper divisors (1730081529887).

12101033320033 is a wasteful number, since it uses less digits than its factorization.

12101033320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170310527.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 12101033320033 its reverse (33002333010121), we get a palindrome (45103366330154).

The spelling of 12101033320033 in words is "twelve trillion, one hundred one billion, thirty-three million, three hundred twenty thousand, thirty-three".