121011000133 has 4 divisors (see below), whose sum is σ = 127380000160. Its totient is φ = 114642000108.

The previous prime is 121011000083. The next prime is 121011000199. The reversal of 121011000133 is 331000110121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121011000133 - 2²¹ = 121008902981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121011000433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3184499985 + ... + 3184500022.

It is an arithmetic number, because the mean of its divisors is an integer number (31845000040).

Almost surely, 2^121011000133 is an apocalyptic number.

It is an amenable number.

121011000133 is a deficient number, since it is larger than the sum of its proper divisors (6369000027).

121011000133 is an equidigital number, since it uses as much as digits as its factorization.

121011000133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6369000026.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 121011000133 its reverse (331000110121), we get a palindrome (452011110254).

The spelling of 121011000133 in words is "one hundred twenty-one billion, eleven million, one hundred thirty-three", and thus it is an aban number.