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12101100343 = 71290358711
BaseRepresentation
bin10110100010100100…
…00010001100110111
31011020100100120221121
423101102002030313
5144240340202333
65320440324411
7605606440633
oct132122021467
934210316847
1012101100343
11514a834882
122418773707
1311ab0a2107
1482b217dc3
154ac59132d
hex2d1482337

12101100343 has 8 divisors (see below), whose sum is σ = 12275974656. Its totient is φ = 11926349400.

The previous prime is 12101100313. The next prime is 12101100353. The reversal of 12101100343 is 34300110121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12101100343 is a prime.

It is a super-2 number, since 2×121011003432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12101100313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176758 + ... + 235468.

It is an arithmetic number, because the mean of its divisors is an integer number (1534496832).

Almost surely, 212101100343 is an apocalyptic number.

12101100343 is a deficient number, since it is larger than the sum of its proper divisors (174874313).

12101100343 is an equidigital number, since it uses as much as digits as its factorization.

12101100343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61685.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12101100343 its reverse (34300110121), we get a palindrome (46401210464).

The spelling of 12101100343 in words is "twelve billion, one hundred one million, one hundred thousand, three hundred forty-three".

Divisors: 1 71 2903 58711 206113 4168481 170438033 12101100343