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121011120105 = 3529278186483
BaseRepresentation
bin111000010110011010…
…0110010011111101001
3102120100110202211112020
41300230310302133221
53440312321320410
6131331452135053
711512524356301
oct1605464623751
9376313684466
10121011120105
1147358693677
121b552467489
13b546818ba5
145bdd74a601
153233b31a70
hex1c2cd327e9

121011120105 has 16 divisors (see below), whose sum is σ = 200294268480. Its totient is φ = 62313771968.

The previous prime is 121011120091. The next prime is 121011120143. The reversal of 121011120105 is 501021110121.

It is a cyclic number.

It is not a de Polignac number, because 121011120105 - 223 = 121002731497 is a prime.

It is a super-2 number, since 2×1210111201052 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139092807 + ... + 139093676.

It is an arithmetic number, because the mean of its divisors is an integer number (12518391780).

Almost surely, 2121011120105 is an apocalyptic number.

121011120105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

121011120105 is a deficient number, since it is larger than the sum of its proper divisors (79283148375).

121011120105 is a wasteful number, since it uses less digits than its factorization.

121011120105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278186520.

The product of its (nonzero) digits is 20, while the sum is 15.

Adding to 121011120105 its reverse (501021110121), we get a palindrome (622032230226).

The spelling of 121011120105 in words is "one hundred twenty-one billion, eleven million, one hundred twenty thousand, one hundred five".

Divisors: 1 3 5 15 29 87 145 435 278186483 834559449 1390932415 4172797245 8067408007 24202224021 40337040035 121011120105