121011120143 has 2 divisors, whose sum is σ = 121011120144. Its totient is φ = 121011120142.

The previous prime is 121011120091. The next prime is 121011120157. The reversal of 121011120143 is 341021110121.

It is a strong prime.

It is an emirp because it is prime and its reverse (341021110121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121011120143 - 2¹² = 121011116047 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121011120193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505560071 + 60505560072.

It is an arithmetic number, because the mean of its divisors is an integer number (60505560072).

Almost surely, 2^121011120143 is an apocalyptic number.

121011120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

121011120143 is an equidigital number, since it uses as much as digits as its factorization.

121011120143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 121011120143 its reverse (341021110121), we get a palindrome (462032230264).

The spelling of 121011120143 in words is "one hundred twenty-one billion, eleven million, one hundred twenty thousand, one hundred forty-three".