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12101114303 = 61198378923
BaseRepresentation
bin10110100010100100…
…00101100110111111
31011020100101022002122
423101102011212333
5144240341124203
65320440513155
7605606526425
oct132122054677
934210338078
1012101114303
11514a844313
12241877b7bb
1311ab0a8585
1482b21d115
154ac595538
hex2d14859bf

12101114303 has 4 divisors (see below), whose sum is σ = 12299493288. Its totient is φ = 11902735320.

The previous prime is 12101114261. The next prime is 12101114327. The reversal of 12101114303 is 30341110121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12101114303 - 210 = 12101113279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12101104303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99189401 + ... + 99189522.

It is an arithmetic number, because the mean of its divisors is an integer number (3074873322).

Almost surely, 212101114303 is an apocalyptic number.

12101114303 is a deficient number, since it is larger than the sum of its proper divisors (198378985).

12101114303 is an equidigital number, since it uses as much as digits as its factorization.

12101114303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198378984.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12101114303 its reverse (30341110121), we get a palindrome (42442224424).

The spelling of 12101114303 in words is "twelve billion, one hundred one million, one hundred fourteen thousand, three hundred three".

Divisors: 1 61 198378923 12101114303