Base | Representation |
---|---|
bin | 1011000000011000011111… |
… | …0110111111100101100101 |
3 | 1120211212022120220012112202 |
4 | 2300012013312333211211 |
5 | 3041231230231310341 |
6 | 41423114320424245 |
7 | 2356166033434562 |
oct | 260060766774545 |
9 | 46755276805482 |
10 | 12101202213221 |
11 | 3946100198550 |
12 | 1435364178085 |
13 | 69a1a52b9ca4 |
14 | 2db9b6587869 |
15 | 15eba798179b |
hex | b0187dbf965 |
12101202213221 has 4 divisors (see below), whose sum is σ = 13201311505344. Its totient is φ = 11001092921100.
The previous prime is 12101202213197. The next prime is 12101202213251. The reversal of 12101202213221 is 12231220210121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12101202213221 - 218 = 12101201951077 is a prime.
It is a super-4 number, since 4×121012022132214 (a number of 53 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12101202213193 and 12101202213202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12101202213251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550054646045 + ... + 550054646066.
It is an arithmetic number, because the mean of its divisors is an integer number (3300327876336).
Almost surely, 212101202213221 is an apocalyptic number.
12101202213221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
12101202213221 is a deficient number, since it is larger than the sum of its proper divisors (1100109292123).
12101202213221 is a wasteful number, since it uses less digits than its factorization.
12101202213221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1100109292122.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 12101202213221 its reverse (12231220210121), we get a palindrome (24332422423342).
The spelling of 12101202213221 in words is "twelve trillion, one hundred one billion, two hundred two million, two hundred thirteen thousand, two hundred twenty-one".
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