Base | Representation |
---|---|
bin | 10001100111000001100… |
… | …011001000010101000011 |
3 | 11021200120020202222000021 |
4 | 101213001203020111003 |
5 | 124311323023201034 |
6 | 2323532154234311 |
7 | 153300136653205 |
oct | 21470143102503 |
9 | 4250506688007 |
10 | 1210133022019 |
11 | 42723a5a7559 |
12 | 176647125997 |
13 | 8a165a0b31c |
14 | 427dc1d6775 |
15 | 217295c26b4 |
hex | 119c18c8543 |
1210133022019 has 4 divisors (see below), whose sum is σ = 1210139979496. Its totient is φ = 1210126064544.
The previous prime is 1210133021959. The next prime is 1210133022023. The reversal of 1210133022019 is 9102203310121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1210133022019 - 223 = 1210124633411 is a prime.
It is a super-2 number, since 2×12101330220192 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1210133021984 and 1210133022002.
It is not an unprimeable number, because it can be changed into a prime (1210133022719) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3210969 + ... + 3567994.
It is an arithmetic number, because the mean of its divisors is an integer number (302534994874).
Almost surely, 21210133022019 is an apocalyptic number.
1210133022019 is a deficient number, since it is larger than the sum of its proper divisors (6957477).
1210133022019 is an equidigital number, since it uses as much as digits as its factorization.
1210133022019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6957476.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 1210133022019 in words is "one trillion, two hundred ten billion, one hundred thirty-three million, twenty-two thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •