Base | Representation |
---|---|
bin | 1011000000011011100000… |
… | …1100011100010001101010 |
3 | 1120211221102002210122212111 |
4 | 2300012320030130101222 |
5 | 3041234410331021442 |
6 | 41423331005432534 |
7 | 2356225111300021 |
oct | 260067014342152 |
9 | 46757362718774 |
10 | 12102013142122 |
11 | 3946486a13422 |
12 | 143554b86b74a |
13 | 69a2a42c8487 |
14 | 2dba521598b8 |
15 | 15ec03c66b17 |
hex | b01b831c46a |
12102013142122 has 4 divisors (see below), whose sum is σ = 18153019713186. Its totient is φ = 6051006571060.
The previous prime is 12102013142099. The next prime is 12102013142123. The reversal of 12102013142122 is 22124131020121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7472454149241 + 4629558992881 = 2733579^2 + 2151641^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12102013142093 and 12102013142102.
It is not an unprimeable number, because it can be changed into a prime (12102013142123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3025503285529 + ... + 3025503285532.
Almost surely, 212102013142122 is an apocalyptic number.
12102013142122 is a deficient number, since it is larger than the sum of its proper divisors (6051006571064).
12102013142122 is an equidigital number, since it uses as much as digits as its factorization.
12102013142122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6051006571063.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12102013142122 its reverse (22124131020121), we get a palindrome (34226144162243).
The spelling of 12102013142122 in words is "twelve trillion, one hundred two billion, thirteen million, one hundred forty-two thousand, one hundred twenty-two".
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