Base | Representation |
---|---|
bin | 1011000000011011100011… |
… | …0101110111110110111001 |
3 | 1120211221102212020110012021 |
4 | 2300012320311313312321 |
5 | 3041234421121044001 |
6 | 41423332034314441 |
7 | 2356225302513262 |
oct | 260067065676671 |
9 | 46757385213167 |
10 | 12102024003001 |
11 | 3946492061359 |
12 | 1435553428a21 |
13 | 69a2a662bb2a |
14 | 2dba53785969 |
15 | 15ec04baeba1 |
hex | b01b8d77db9 |
12102024003001 has 4 divisors (see below), whose sum is σ = 12130907115600. Its totient is φ = 12073140890404.
The previous prime is 12102024002989. The next prime is 12102024003029. The reversal of 12102024003001 is 10030042020121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12102024003001 - 223 = 12102015614393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12102024003061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14441555671 + ... + 14441556508.
It is an arithmetic number, because the mean of its divisors is an integer number (3032726778900).
Almost surely, 212102024003001 is an apocalyptic number.
It is an amenable number.
12102024003001 is a deficient number, since it is larger than the sum of its proper divisors (28883112599).
12102024003001 is an equidigital number, since it uses as much as digits as its factorization.
12102024003001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28883112598.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 12102024003001 its reverse (10030042020121), we get a palindrome (22132066023122).
The spelling of 12102024003001 in words is "twelve trillion, one hundred two billion, twenty-four million, three thousand, one".
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