12102100301113 has 4 divisors (see below), whose sum is σ = 12739052948560. Its totient is φ = 11465147653668.

The previous prime is 12102100301069. The next prime is 12102100301117. The reversal of 12102100301113 is 31110300120121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12102100301113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12102100301117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318476323695 + ... + 318476323732.

It is an arithmetic number, because the mean of its divisors is an integer number (3184763237140).

Almost surely, 2^{12102100301113} is an apocalyptic number.

It is an amenable number.

12102100301113 is a deficient number, since it is larger than the sum of its proper divisors (636952647447).

12102100301113 is an equidigital number, since it uses as much as digits as its factorization.

12102100301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636952647446.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 12102100301113 its reverse (31110300120121), we get a palindrome (43212400421234).

The spelling of 12102100301113 in words is "twelve trillion, one hundred two billion, one hundred million, three hundred one thousand, one hundred thirteen".